A pedestrian and a cyclist start simultaneously towards each other form aurangabad and paithan which are 40 km apart and meet 2 hours after the start. Then they resumed their trips and the cyclist arrives at aurangabad 7 hours 30 minutes earlier than the pedestrian arrives at paithan . Which of these could be the speed of the pedestrian ?
Answers
speed of the pedestrian = 4 km/hr in 40 km distance they meet after 2 hrs and cyclist reaches 7 hr 30 min before than pedestrian
Step-by-step explanation:
Distance = 40 km
Speed of Pedestrian = S km / hr
Distance Covered in 2hr by Pedestrian = 2S km
Distance covered by Cyclist in 2 hrs = 40 - 2S km
Speed of Cyclist = (40 - 2S)/2 = 20 - S km/Hr
Time Taken by Cyclist for trip is 7 hr 30 less than Pedestrian
=> 40/ (20 - S) + 7.5 = 40/S
=> 40S + 150S - 7.5S² = 800 - 40S
=> 7.5S² - 230S + 800 = 0
=> 7.5S² - 30S -200S + 800 = 0
=> 7.5S(S - 4) - 200(S - 4) =0
=> (S - 4)(7.5S - 200) = 0
=> S = 4 or S = 200/7.5 = 80/3
80/3 is not possible as Speed of cyclist + pedastrian = 20 km/hr only
speed of the pedestrian = 4 km/hr
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Step-by-step explanation:
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