A peice of thin wire in the shape of an equilateral triangle of side 3.14cm is bent in to a ring with no loss in wire. Find diameter of the sing(pie=3.14)
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Side equilateral triangle
= 3.14 cm
Perimeter
= 3 × 3.14 = 9.42 cm
πd = 9.42
πd = 9.42
3.14×d = 9.42
d = 3 cm.
Side equilateral triangle
= 3.14 cm
Perimeter
= 3 × 3.14 = 9.42 cm
πd = 9.42
πd = 9.42
3.14×d = 9.42
d = 3 cm.
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