Question

A peice of wire is bent in the shape an equilateral triangle of side 6.6cm. it is rebent to form a circle. Find the diameter of circle

Answer 1

PERIMETER of triangle = 3× 6.6= 19.8 cm
it is rebent to form circle
so circumference of circle = 19.8 cm
but circumference = 2 pie × r
so 2r = circumference ÷ pie
= 19.8 ÷ (22/7)
= (19.8× 7)÷ 22
=138.6÷22
2r = 6.3cm
so d = 6.3 cm
hope it will help u