Question

A peice of wool is rubbed against a pvc strip. What will be the charge on the strip, if approximately 2x10^12 electron are transferred from the wool to the pvc strip?

Answer 1

Given :

• Number of electrons (n) = $\sf{2 \: \times \: 10^{12}}$

To Find :

• Charge on the strip

Solution :

We're given that a piece of wool is rubbed against a PCV strip. And the number of electrons transferred from wool to PVC strip are 2 × 10^12 electrons.

Here in this question we've to use formula for quantization of charge :

$\bigstar \: \: \boxed{\sf{Q \: = \: \pm \: ne}}$

Where,

• Q is charge on the strip
• n is number of electrons
• e is charge on electron

And also the charge of an electron is 1.6 * 10^-19 C

⇒Q = ± ne

⇒Q = (1.6 * 10^-19) × (2 × 10^12)

⇒Q = (1.6 * 2) * 10^(-19 + 12)

⇒Q = (1.6 * 2) * 10^-7

⇒Q = 3.2 * 10^-7

$\therefore$ Charge on the PVC strip is 3.2 * 10^(-7) C

• SI unit of Charge is Coulomb

Answer 2

Given :

Number of electrons (n) = 2× 10¹²

To Find :

We have to find the Charge on the strip ?

Explanation :

WE KNOW THE FORMULA TO CALCULATE THE CHARGE ON STRIP :

Q = ± ne

________________[Putting Values]

→Q = ± ne

→Q = (1.6 × 10^-19) × (2 × 10^12)

→Q = (1.6 × 2) × 10^{12 + (-19) }   [∵ When base are same powers are added]

→Q = (1.6 × 2) × 10^(-7)

→Q = 3.2 × 10^(-7)

∴Charge on the PVC strip is 3.2 × 10^(-7) C