Question

A pellet carrying a charge of 0.5 coulomb is accelerated through a P.D of 2000 volt. It attains a kinetic energy equal to​

Answer 1

Answer:

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Answer 2

Given:

The charge of the pellet, q = 0.5 C

The pellet is accelerated through a potential difference, V = 2000 Volts

To find:

Kinetic Energy attained by the pellet

Solution:

We know the kinetic energy attained by a charged particle having a charge "q" and accelerated through a potential difference "V" is given by

$\boxed{\bold{E\:=\:qV}}$

Now, we will substitute the given values of q and V in the formula above,

E = 0.5 C × 2000 V

⇒ E = 1000 Joules

Thus, the pellet attains kinetic energy equal to 1000 J.

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