A Pelton wheel Of 1.2 m mean bucket diameter works under a head Of 650 m. The jet deflection is 1650 and its relative velocity is reduced over the buckets by 15% due to friction. Ifthe water is to leave the bucket without whirl, determine the rotational speed of the wheel. The coefficient Of velocity is Cv = 0.98.
(a) 786.38 rpm (b) 1425.36 rpm (c) 320.2 rpm (d) 480.6 rpm
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Explanation:
it/s 0.05 m3/s
H= 150 m
Kv 1
diameter 60 cm 0.6 m3/s
speed 600 rpm
jet deflect through 180 °
K (assume) 0.95
Power available in the nozzle= 73575 W *ρgQH
velocity of jet V= 54.25 m/s *V1=Vw1 =Kv√(2gH)
Tangential velocity of the wheel u = 18.85 m/s * u=πDN /60
blade to speed ratio , ρ=u/V 0.35
Φ = 0 °
hydraulic efficiency ηh= 0.884 * ηh=2(ρ-ρ^2)(1+KcosΦ)
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