Question

A pen is dropped from a height H. When it reaches the ground, its velocity
is 50 m/s. The value of H is (g = 9.8m/s^2):​

Answer 1

Answer:

125m(approx)

Explanation:

acc to nlm,

v^2=u^2+2as

here u=0

so 50^2=0+2*9.8*s

s=2500\2*9.8

s≈125m.

Answer 2

Answer:

127.5 m

Explanation:

Given:

v = 50 m/s

u = 0 ( since the object is starting from rest )

g = 9.8m/s²

H = x

Formula:

third law of motion says v² - u² = 2gh

h = v² - u²/2g

Solution:

x = 50² - 0²/ 2×9.8

= 2500 - 0 / 2×9.8

= 2500 / 19.6

= 127.5

x = 127.5

h= 127.5m