Question

A pen is placed 11.0 cm from a concave spherical mirror produces a real image 13.2 cm from the mirror.



What is the focal length of the mirror?



What is the magnification of the image?



If the pen is placed 27.0 cm from the mirror, what is the new position of the image?



What is the magnification of the new image?



Is the new image real or virtual?

Answer 1

Explanation:

1/f = 1/u + 1/v. u = 11cm and v = 13.2 cm

1/f = 1/11 + 1/ 13.2 = 1/ 6

Hence f = 6 cm.