A pen stand made of a wood is in the shape of a cuboid with four conical depression to hold pens. The dimensions of the cuboid are 15 cm by 10 cm by 3.5 cm. The diameter of each of the depression is 1 cm and the depth is 1.4 cm. Find the volume of wood in the entire stand.
Answers
Answered by
26
Heya !!!
Diameter of each conical depression (D) = 1 cm
Radius of each conical depression (R) = 1/2 cm.
Depth of each conical depression (H) = 1.4 cm.
Volume of the wood in the stand = (Volume of the cuboid ) - (Volume of 4 conical depressions).
=> ( 15 × 10 × 3.5) - ( 4 × 1/3 πR²H )
=> ( 525 ) - ( 4/3 × 22/7 × 1/2 × 1/2 × 1.4)
=> ( 525 - 4.4/3) cm³.
=>( 525 - 1.47 ) cm³.
=> 523.53 cm³.
HOPE IT WILL HELP YOU....... :-)
Diameter of each conical depression (D) = 1 cm
Radius of each conical depression (R) = 1/2 cm.
Depth of each conical depression (H) = 1.4 cm.
Volume of the wood in the stand = (Volume of the cuboid ) - (Volume of 4 conical depressions).
=> ( 15 × 10 × 3.5) - ( 4 × 1/3 πR²H )
=> ( 525 ) - ( 4/3 × 22/7 × 1/2 × 1/2 × 1.4)
=> ( 525 - 4.4/3) cm³.
=>( 525 - 1.47 ) cm³.
=> 523.53 cm³.
HOPE IT WILL HELP YOU....... :-)
sourav232:
thank you so much
Answered by
19
Given,
The dimensions of the cuboid:
Length (l) = 15 cm
Breadth (b) = 10 cm
Height (h) = 3.5 cm
The dimensions of the cone:
The radius of each depression is 0.5 cm and depth is 1.4 cm.
Height = 1.4 cm
Radius = 0.5 cm
Solution:
Volume of the wood = Volume of cuboid - 4(volume of cone)
Volume of cuboid:
Therefore the volume of wood is 523.54 cubic units.
Attachments:
Similar questions