a pencil costs $0.25 more than an eraser. if the cost of 8 pencils is $6.80, what is the cost of 1 eraser
Answers
Answered by
3
-_+
Cost of a pencil = $0.25 + cost of an eraser (let it be as x)
=) Cost of 8 pencils = $6.80
=) 8($0.25 + x) = $6.80
=) $2 + 8x = $6.80
=) 8x = $4.80
=) x = $0.60
+_-
Cost of a pencil = $0.25 + cost of an eraser (let it be as x)
=) Cost of 8 pencils = $6.80
=) 8($0.25 + x) = $6.80
=) $2 + 8x = $6.80
=) 8x = $4.80
=) x = $0.60
+_-
audreyorosha:
thank u so much for answering so quickly
Answered by
2
Answer:
Step-by-step explanation:
Let the price of eraserbe$x.
Price of pencil$ 0.25+x
Cost of 8 pencil $6.80
Cost of 1 pencil$6.80÷8 =$0.85.
By the problem
0.25+x=0.85
or,x =0.85-0.25=0.6
Price of eraser $0.6
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