a pencil given in the adjacent figure is sharpened with no overall loss of length to produce a perfect cone at one end. find the volume of the peel.
Answers
Answer:
Diameter of the pencil = 1cm
The length of the conical portion is 2cm.
To find out,
Calculate the volume of the shavings.
Solution:
Radius of the pencil is 0.5cm.
Length of the conical portion( h) = 2cm
Volume of peels = = Volume of cylinder of length 2CM and base radius 0.5cm - Volume of the cone formed by this cylinder.
\begin{gathered}Volume \: of \: peels \: \\ \\ = \pi \: {r}^{2} h - \frac{1}{3} \pi \: {r}^{2}h \\ \\ = \frac{2}{3} \pi \: {r}^{2} h \\ \\ = \frac{2}{3} \times \frac{355}{113} \times 0.5 \times 0.5 \times 2 \\ \\ = 1.05 \: {cm}^{3} \end{gathered}
Volumeofpeels
=πr
2
h−
3
1
πr
2
h
=
3
2
πr
2
h
=
3
2
×
113
355
×0.5×0.5×2
=1.05cm
3
Therefore the volume of the peels is 1.05 cubic units.
Answer:
hey cool name and nice profile picture
Step-by-step explanation:
The fastest-spinning neutron star known is PSR J1748-2446ad, rotating at a rate of 716 times a second or 43,000 revolutions per minute, giving a linear speed at the surface on the order of 0.24 c (i.e., nearly a quarter the speed of light).