Question

a pencil of hieght 2 cm is kept upright 5cm away from a convex mirror of radius of curvature 20cm. find position , height and nature of the image.​

Answer 1

Answer:

This is your answer............

Answer 2

The image formed at the distance is 3.33 cm and the height of the virtual image is 1.332 cm.

Explanation:

Given that,

Height of pencil= 2 cm

Object distance = 5 cm

Radius of curvature = 20 cm

We need to calculate the image distance

Using formula of mirror

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

Where, v = image distance

u = object distance

f = focal length

Put the value into the formula

$\dfrac{1}{10}=\dfrac{1}{v}+\dfrac{1}{-5}$

$\dfrac{1}{v}=\dfrac{1}{10}+\dfrac{1}{5}$

$\dfrac{1}{v}=\dfrac{3}{10}$

$v=3.33\ cm$

We need to calculate the height of the image

Using formula of magnification

$m =\dfrac{v}{u}=\dfrac{h'}{h}$

Put the value into the formula

$\dfrac{3.33}{5}=\dfrac{h'}{2}$

$h'=\dfrac{3.33\times2}{5}$

$h'=1.332\ cm$

Hence, The image formed at the distance is 3.33 cm and the height of the virtual image is 1.332 cm.

Learn more:

Topic : convex mirror

https://brainly.in/question/9151863