Physics, asked by chandanchandanskm, 12 days ago

A pendlulum oscillator 40 times in 4 second find its time period and frequency​

Answers

Answered by bojjanagarajubjp
0

Answer:

Frequency is defined as the number of oscillations per unit time. Time = 4 sec. Time Period = (4/40) = 0.1 sec. Frequency = (Number of Oscillations)/ (Time taken)Frequency = (40/4) =10Hz.

Explanation:

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Answered by wwwsneh10tha4
0

Answer:

Time period = time/ no. of oscillations

Time period= 4 ÷ 40

Time period = 0.1 sec

Frequency= no. of oscillations ÷ time taken

Frequency = 40÷4

Frequency = 10Hz

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