Question

a pendulam completes 2 ocillations in 5 seconds, what is its time period? If g =9.8 ms^2 , find its length. ​

Answer 1

Explanation:

Time period=(oscillation per second )^-1

=(2/5)^-1

=5/2

=2.5s

length=t²/4π²*g

=(2.5)²/4π²*9.8

=1.55m