Question

A pendulam copletes its iscillation in 5 seconds what is time period if g = 9.8m/s2, find its length​

Answer 1

Answer:

$t = 2\pi \sqrt{ \frac{l}{g} }$

as, time period is 5 so

$5 = 2(3.14) \sqrt{ \frac{l}{9.8} }$

taking square on both sides

$25 = 4(3.14) ^{2} ( \frac{l}{9.8} )$

$l = \frac{25 \times 9.8}{39.438}$

$l = 6.21 \: m$