Science, asked by singhankitvishe7534, 11 months ago

A pendulum A oscillates 16 times in 4 seconds and pendulum B oscillates 40 times in 8 seconds. The number of oscillation completed by pendulum A in the time equal to the time taken by pendulum B to complete 100 oscillations

Answers

Answered by Govindthapak
160

Answer:

Answer is 80 oscillations

Explanation:

oscillation rate of pendulum A

 \frac{16}{4}  = 4 \: oscillations \: per \: sec \\

oscillation rate of pendulum B

 \frac{40}{8}  = 5 \: osci \: per \: sec

time taken by B in 100 oscillations

 \frac{100}{5}  = 20 \: sec

number of oscillation done by A in 20 sec

20 \times 4 = 80 \: oscillations

Answered by barnikapaulviid
2

Answer:

Answer is 80 oscillations

Explanation:

oscillation rate of pendulum A

oscillation rate of pendulum B

time taken by B in 100 oscillations

number of oscillation done by A in 20 sec

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