Question

A pendulum A oscillates 16 times in 4 seconds and
pendulum B oscillates 40 times in 8 seconds. The
number of oscillations completed by pendulum A in
the time equal to the time taken by pendulum to
complete 100 osoillations is
(1) 160
(2) 80
(3) 40
(4) 320​

Answer 1

Answer:

80 oscillations

Explanation:

• first consider pendulum a it covers 16 oscillations per 4 seconds that means it covers 4 oscillations in 1 second (hint: divide 16 by 4)

similarly pendulum b covers 5 oscillations in 1 second (hint: divide 40 by 8)

• given number of oscillations completed by a is equal to 100 oscillations of b

• let time taken to make 100 oscillations of b be x

• we know it completes 5 oscillations in 1 second

• that means it covers 100 oscillations in 20 second

• the number of oscillation covered by a in 20 seconds is 80