a pendulum bob of 1N is held at an angle teta from the vertical by a horizontal force of 2N as shown . The tension in the string supporting the pendulum bob (in Newton ) is
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◆【Solution】◆
Mg = 1N
Angle with verticle = ∆
Ma = 2N
Tension = T
Where m is the mass of bob
Bob is in stationary state so all the forces balance each oither.
♂ Horizontal forces. ♂
TSin∆ = Ma
TSin∆ = 2N.....(1)
♂ Verticle force ♂
Tcos∆ = mg
Tcos∆ = 1N......(2)
Add squares of (1) and (2)
T²(Cos²∆ + Sin²∆) = 4 + 1
T² = 5
◆【Tension = √5】◆
#answerwithquality
#BAL
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