A pendulum bob of mass 50 g is suspended on a string from the ceiling of an elevator which is moving downwards with an acceleration 1.5 metre per second square . Draw the free body diagram using the non inertial frame of,reference and determine the tension in the string . ( Take g = 10 ms-2)
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m = 50 gm, g = 10 m/s^2
acceleration downwards of the elevator , a = 1.5 m/s^2
Frame of reference:
non-inertial frame. A coordinate access attached to the elevator.
In the non-inertial frame, we add a pseudo force on each object having a mass in the direction opposite to the movement of the frame. So add a pseudo force on pendulum upwards = m a = 0.050 * 1.5 = 0.075 N
There is the weight of pendulum m g = 0.50 N acting downwards.
There is tension T in the string acting upwards on the pendulum.
As the pendulum is at rest in the non-inertial frame:
T + 0.075 N = 0.50 N
T = 0.425 N
acceleration downwards of the elevator , a = 1.5 m/s^2
Frame of reference:
non-inertial frame. A coordinate access attached to the elevator.
In the non-inertial frame, we add a pseudo force on each object having a mass in the direction opposite to the movement of the frame. So add a pseudo force on pendulum upwards = m a = 0.050 * 1.5 = 0.075 N
There is the weight of pendulum m g = 0.50 N acting downwards.
There is tension T in the string acting upwards on the pendulum.
As the pendulum is at rest in the non-inertial frame:
T + 0.075 N = 0.50 N
T = 0.425 N
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