Question

a pendulum bob on a 2m string is displaced 60 degree from the vertical and then released. what is the speed of the bob as it passes through the lowest point in its path

Answer 1

Explanation:

Velocity of bob v=2gl(1−cosθ)−−−−−−−−−−√

=2×9.8×2×(1−cos60∘)−−−−−−−−−−−−−−−−−−−−−√

v=2×9.8−−−−−−√m/s