Question

A pendulum clock is 5 sec fast at 15 celsius and 10 secs slow at 30 degree celsius find temperature when it shows correct time

Answer 1

$\mathfrak{The\:Answer\:is}$

now it is given that clock is 5 seconds fast each day i.e. 1.16 ... so clock will give correct time at 20 oC ... we get the temp at which clock gives correct time.10/5=(30-t)/2 .

$\boxed{Hope\:This\:Helps}$

Answer 2

The temperature when correct time is shown is 20°

Time when clock is fast = 5 seconds (Given)

Temperature at which clock is fast = 15° (Given)

Time when clock is slow = 10 seconds (Given)

Temperature at which clock is slow = 30° (Given)

Let the temperature at which the clock shows right time be = t

The change in period of pendulum when temperature changes will be -

ΔT = 1/2∝ФT

5 = 1/2 a (t-15)T

Now, at 30° there will be a loss of 10 seconds

Thus,

- 10 = 1/2 a (t-30)T

t = 20

Thus, the temperature when correct time is shown is 20°