A pendulum clock keeps perfect time at a location where the acceleration due to gravity is exactly 9.8 meter per second square .when a clock is moved to a higher altitude, it loses 80.0 s per day. Find the value of g at this new location?
answer : 9.78 meter pr second square..
I need solution ??
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given = A pendulum clock keeps perfect time at a location where the acceleration due to gravity is exactly 9.8 meter per second square .when a clock is moved to a higher altitude, it loses 80.0 s per day. Find the value of g at this new location?
solution =
Acceleration due to gravity at the surface of the earth is 9.8 meter /sec². g is also known as a gravitational constant which has fixed value 9.8m/s².
also we can calculate by using the formula ,
Earth as assumed to be a uniform solid sphere with a mean density.
Density = mass/volume
ρ = M/[4/3 πR3]
M = ρ × [4/3 πR3]
We know that, g = GM/R2.
g = 4/3 [πρRG]
after putting the value in this formula we get the value of g that is 9.8
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