Physics, asked by saniabarbie777, 6 months ago

A pendulum clock keeps perfect time at a location where the acceleration due to gravity is exactly 9.8 meter per second square .when a clock is moved to a higher altitude, it loses 80.0 s per day. Find the value of g at this new location?


answer : 9.78 meter pr second square..
I need solution ??

Answers

Answered by studay07
5

Answer:

given = A pendulum clock keeps perfect time at a location where the acceleration due to gravity is exactly 9.8 meter per second square .when a clock is moved to a higher altitude, it loses 80.0 s per day. Find the value of g at this new location?

solution =

Acceleration due to gravity at the surface of the earth is 9.8 meter /sec². g is also known as a gravitational constant which has fixed value 9.8m/s².

also we can calculate by using the formula ,

Earth as assumed to be a uniform solid sphere with a mean density.  

Density = mass/volume

           ρ = M/[4/3 πR3]

          M = ρ × [4/3 πR3]

We know that, g = GM/R2.

g = 4/3 [πρRG]

after putting the value in this formula we get the value of g that is 9.8

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