A pendulum clock loses 12 s a day if the temperature is 40°C and gains 4 s in a day if the temperature is 20°C.
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Time loss or gain is given by
Δt=(ΔTT)t=12αθ.t
12=12α(40−θ0)×Id ----(1)
4=12α(θ0−20)×Id ----(2)
(1)(2) gives
3=(40−θ0)(θ0−20)
Solving θ0=25∘C and putting in (2)
α=85×29×60×60
=1.85×10−5/∘C
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