a pendulum completes 2 oscillation in 5 sec (a) what is its time period ? (b) If g = 9.8 m/s, find its length
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Answer:
Time period T= 1/ oscillations per second
=1/(2/5) =5/2=2.5 s
Length, l= T^2/4π^2 ×g
= 2.5×2.5/4π^2 ×9.8
=1.55m
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