Question

A pendulum completes 2 oscillation in 5 seconds what is its time period

Answer 1

T=2π√l/g

squaring on both sides , we get

T^2= 4π^2(l/g)

from here

l =(T^2×g)/4π^2

given that

T=5s for two oscillations

so, for one oscillation T=5/2=2.5s

g=9.8 m/s^2

so,

l = (5^2×9.8)/4×3.14^2

=6.2mts

Answer 2

Answer:

time taken by the pendulum to complete one oscillation is 2/5s=0.4s