Question

• A pendulum completes 2 oscillations in 5 s.
(a) What is its time period ? (b) If g = 9.8 m s-2, find
its length.​

Answer 1

Answer: 6.2mts

Explanation:

we know that time period of a simple pendulum

T=2π√l/g

squaring on both sides , we get

T^2= 4π^2(l/g)

from here

l =(T^2×g)/4π^2

given that

T=5s for two oscillations

so, for one oscillation T=5/2=2.5s

g=9.8 m/s^2

so,

l = (5^2×9.8)/4×3.14^2

=6.2mts

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Answer 2

Answer:

a) time period = time taken /no.of oscillation

=5/2=2.5s