Question

a pendulum completes 4 oscillations in 6 sec at a place where g = 10 find the time period and length​

Answer 1

Answer:

T = 1.5s, L = 0.57m

Explanation:

a pendulum completes 4 oscillations in 6 sec

time period, T = 6/4 = 1.5 s

Let the length of the pendulum = L

we know that:

$T = 2 \pi\sqrt{\frac{L}{g}} \\ \\ \Rightarrow 1.5 = 2 \pi\sqrt{\frac{L}{10}}\\ \\ \Rightarrow 1.5 = 6.28 \sqrt{\frac{L}{10}}\\ \\ \Rightarrow L={(\frac{1.5}{6.28}) }^{2} \times 10 = 0.57m$

Hence time period is 1.5 second and length of pendulum is 0.57 m