A pendulum completes two oscillation in 5 s. what is its time period. If g=9.8ms-2, Find its length.
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Answer:
T=2π√(L/g)
T of one oscillation =5/2
g=9•8
5/2 = 2π√(L/9•8)
sq• both side
25/4=4π^2(L/9•8)
25/16π^2=L/9•8
π =3.14
25/16*(3.14)^2. = L/9.8
25*9.8/16*3.14*3.14. = L
25*9.8/(16*9.86). = L. { (3.14)^2. = 9.86. }
227.0/157.76. = L
L. = 1.43. appox
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