Question

A pendulum completes two oscillation in 5 s. what is its time period. If g=9.8ms-2, Find its length.​

Answer 1

Answer:

T=2π√(L/g)

T of one oscillation =5/2

g=9•8

5/2 = 2π√(L/9•8)

sq• both side

25/4=4π^2(L/9•8)

25/16π^2=L/9•8

π =3.14

25/16*(3.14)^2. = L/9.8

25*9.8/16*3.14*3.14. = L

25*9.8/(16*9.86). = L. { (3.14)^2. = 9.86. }

227.0/157.76. = L

L. = 1.43. appox