A pendulum completes two oscillations in 5 s. (a) what is its time period ?, (b) if g= 9.8 , find its length
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a) In 5 seconds, number of oscillations = 2
In 1 second, number of oscillations = 2/5 = 0.4
SO, FREQUENCY = 0.4 Hz.
Then,
time period (T) = 1/frequency (1/F)
T = 1/0.4 = 2.5 sec.
In 1 second, number of oscillations = 2/5 = 0.4
SO, FREQUENCY = 0.4 Hz.
Then,
time period (T) = 1/frequency (1/F)
T = 1/0.4 = 2.5 sec.
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