A pendulum consist of a wooden bob of mass m and length l a bullet of mass m1 is fired towards the pendulum with a speed v1 the bullet emerges out of the Bob with the speed V1/3 and the Bob just completes motion along a vertical circle then V1 is
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Given:
Wooden bob:
- Mass m
- Length l
Bullet:
- Mass m1
- Speed v1
- Bullet emerges out of the Bob v1/3
- Bob just completes motion along a vertical circle v1
Solution:
Kinetic Energy = 1/2 mv^2
Loss in Kinetic Energy of the bullet = 1/2 m1 (v1/3)^2
In order to make a complete circle of the bob,
√5gl
Where,
g is gravity.
1/2 m (√5gl)^2
Then,
v1 = 3/2 (m/m1) √5gl
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