Question

a pendulum having a period of oscillation of 2 seconds is taken on a planet where g is four times than that on the earth. The period of pendulum would be
(a)2s
(b)1s = ans. tell me how
(c)4s
(d)2√2s

Answer 1

T = 2π √L/g
T prop. 1 /√g
T final will be 1/2T before

Answer 2

I hope this might be helpful for you.