A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator the acceleration of the bob of the pendulum is 20 metre per second square at a distance of 5 M from the mean position the time period of oscillation is
Answers
Answered by
0
Answer:
πs
Explanation:
∣∣=2
⇒20=2(5)
=2/
=2=22=
or
Acceleration of the bob of the pendulum = 20m/s² (Given)
Distance of the bob from mean position = 5m (Given)
Oscillation is the periodic movement at a specified distance from the equilibrium position and repeating itself over and over for a period of time. For example up and down of a spring
The time period of oscillation is πs. Thus,
a = w²x
a = 20w² × 5
w = 2rad/sec
T = 2π/w sec
= π second
Therefore, the time period of oscillation is π second.
Similar questions