A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20m/s2 at a distance of 5 m from the mean position. The time period of oscillation is :
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Kashyapom:
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Answer:
Explanation:
acceleration= w² Asinwt
=w²x (x =Asinwt , distance at any time t)
20= w² *5
w=2
T=2π/w = 2π/2 =π
T=π seconds
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