Physics, asked by Kashyapom, 1 year ago

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20m/s2 at a distance of 5 m from the mean position. The time period of oscillation is :​

Answers

Answered by Chintan7916
20

Hope this will help you..

Attachments:

Kashyapom: thnq so much
Chintan7916: please follow me
Answered by soundmute2711
13

Answer:

Explanation:

acceleration= w² Asinwt

              =w²x               (x =Asinwt  ,   distance at any time t)

           20= w² *5

         w=2

T=2π/w =  2π/2  =π

T=π seconds

Similar questions