A pendulum is made of a rigid rod of mass m and length l and a small bob of mass M is attached at one end. The rod is pivoted at the other end.What is the minimum speed of the bob at its lower end so that it completes a full circle?
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Explanation:
=> Here, A pendulum is made of a rigid rod of mass m and length l and a small bob of mass M is attached at one end. The rod is pivoted at the other end.
=> Suppose velocity of bob of pendulum is V at the lowest point.
=> According to law of energy conservation,
1/2MV^2 + 1/2qw^2 = mg(2L) + mgL
1/2MV^2 + 1/2*(mL^2/3)*(V^2/L^2) = gL (2M + m)
(3M + m)v^2 = gL (12M+6m)
V = √ gL (12M + 6m/3M+m)
Thus, the minimum speed of the bob at its lower end so that it completes a full circle is √ gL (12M + 6m/3M+m).
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