Question

A pendulum kob of mass 50 g is. suspended from the ceiling of an elevator
(a) goes up with acceleration 1.2 m/s²
(b)goes up with decelaration 1.2 m/s²
(c)goes up with uniform velocity
(d) goes down with acceleration 1.2 m/s²
(e) goes down with decelaration
(A) goes down with uniform velocity


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Answer 1

Answer:

$\huge\underline\pink{\tt Hey\:Mate}$

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(a) Goes up with acceleration 1.2ms-2

$\large{\tt T = mg + ma}$

$\large{\tt T= m(g+a)}$

$\large{\tt T = 0.05(10+1.2)}$

$\huge\blue{\boxed{\tt T=0.55N}}</p><p>$

(b) Goes up with decelaration of 1.2ms-2

$\large{\tt T=mg + m(-a)}$

$\large{\tt T = m(g-a)}$

$\large{\tt T = 0.05(10-1.2)}$

$\huge\blue{\boxed{\tt T = 0.44N}}</p><p>$

(c)Goes up with uniform velocity .

$\large{\tt T=mg}$

$\large{\tt T = 0.05×10}$

$\huge\blue{\boxed{\tt T = 0.5N}}</p><p>$

(d)Goes down with acceleration of 1.2ms-2

$\large{\tt T =mg-ma}$

$\large{\tt T = m(g-a)}$

$\large{\tt T = 0.05(10-1.2)}$

$\huge\blue{\boxed{\tt T= 0.44N}}</p><p>$

(e)Goes down with decelaration

$\large{\tt T = mg-m(-a)}$

$\large{\tt T = m(g-a)}$

$\huge\blue{\boxed{\tt T=0.55N}}</p><p>$

(f) Goes down with uniform velocity

$\large{\tt T=mg}$

$\large{\tt T =0.05×10}$

$\huge\blue{\boxed{\tt T = 0.5N}}</p><p>$

Hope this will help uh!!!

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Answer 2

Explanation:

M = 50 gm, g = 10 m/s^2

acceleration downwards of the elevator , a = 1.5 m/s^2

Frame of reference:

non-inertial frame. A coordinate access attached to the elevator.

In the non-inertial frame, we add a pseudo force on each object having a mass in the direction opposite to the movement of the frame. So add a pseudo force on pendulum upwards = m a = 0.050 * 1.5 = 0.075 N

There is the weight of pendulum m g = 0.50 N acting downwards.

There is tension T in the string acting upwards on the pendulum.

As the pendulum is at rest in the non-inertial frame:

T + 0.075 N = 0.50 N

T = 0.425 N