Question

A pendulum ocillayes 40 times in 4 second. find its time period and frequency​

Answer 1

Answer:

Time Period = (4/40) = 0.1 sec. Frequency = (Number of Oscillations)/ (Time taken)Frequency = (40/4) =10Hz.

Answer 2

Question :

A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency​.

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Before, finding the answer. Let's find out how we can find the answer.

• In this question, we are asked to find the Time period and Frequency of the pendulum.
• So, to find the Time period, we have to use the formula of :

$\boxed{ \sf Time \: Period = \dfrac{Time \: taken}{Number \: of \:Oscillations} }$

• Next, to find the Frequency, we have to use the formula of :

$\boxed{ \sf Frequency = \dfrac{Number \: of \: Oscillations }{Time \: taken} }$

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Given :

• Oscillations = 40 times
• Time = 4 second

To find :

• time period and frequency​

Solution :

• Let's find the Time Period.

$\Rightarrow { \sf Time \: Period = \dfrac{Time \: taken}{Number \: of \:Oscillations} }$

                       $\sf { = \dfrac{4}{40} }$

                       $\sf = 0.1$

Therefore, the Time period of the Pendulum is 0.1 sec.

                       

• Now, let's find the Frequency of the Pendulum.

$\Rightarrow { \sf Frequency = \dfrac{Number \: of \: Oscillations }{Time \: taken} }$

                    ${ \sf = \dfrac{40 }{4} }$

                    $\sf = 10$

Therefore, the Frequency of the Pendulum is 10 Hz.