Question

a pendulum of length 2.5 metre is made to oscillate at place where G is 10 second square and calculate the time period of the pendulum​

Answer 1

Explanation:

time period of pendulum is given by

T= 2pi√(l/g)

since l=2.5 m

g=10m/sec^2

pi =3.14

then T= 2*3.14√(2.5/10)

T=2*3.14*0.5

T=3.14sec

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