a pendulum of length 2.5 metre is made to oscillate at place where G is 10 second square and calculate the time period of the pendulum
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Explanation:
time period of pendulum is given by
T= 2pi√(l/g)
since l=2.5 m
g=10m/sec^2
pi =3.14
then T= 2*3.14√(2.5/10)
T=2*3.14*0.5
T=3.14sec
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