Question

a pendulum of mass 8omg and carrying charge of 2×10to the power-8 is at rest in a uniform horizontal electric field is 20kvmto the power-1 .find tension in the thread​

Answer 1

Answer:

Mass =80mg

Charge =2×10

−8

Coulomb

Electric field =20,000Vm

−1

Given, mass =80mg=8×10

−6

kg

charge =q=2×10

−8

C

Let T be the tension in string and θ is the angle if string with vertical.

In equilibrium

Tsinθ=qE⟶(1)

Tcosθ=mg⟶(2)

Divide (1) by (2) we get

tanθ=

mg

qE

⇒tanθ=

80×10

−6

×10

2×10

−8

×2×10

4

tanθ=0.5

θ=tan

−1

(0.5)

θ=27

0

Now,

tension, T=

sinθ

qE

=

sin27

0

2×10

−8

×2×10

4

=8.8×10

−4

V

solution

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