Question

a pendulum oscillate 40 times in 4 seconds. find its time period and frequency​

Answer 1

frequency is define as number of oscillation per sec

t=4 sec

time period= 4/40=0.1 sec

frequency= no. of oscillation/ time

40/4= 10Hz

Answer 2

Given :-

Number of oscillations - 40

Time taken - 4 s

To find :-

Time period

Frequency

Solution:-

As we know that,

$\boxed{ \rm \pink{ \: Time \: \: period \: = \frac{Time \: taken}{No.of \: oscillations} }}$

Substituting the values,

$\: \: \: \: \rm \: \implies \: Time \: period = \dfrac{4}{40}$

$\: \: \: \: \rm \: \implies \: Time \: period = \dfrac{1}{10}$

$\: \: \: \: \rm \: \implies \: Time \: period = 0.1 \: s$

So, the time period is 0.1 s

__________________________

Also we know that,

$\boxed{ \rm \pink{ \: Frequency \: = \frac{1}{time \: taken \: } }}$

$\rm \: \implies \: Frequency \: = \dfrac{1}{0.1}$

$\: \: \: \: \: \: \rm \: \implies \: Frequency \: = \dfrac{1}{ \dfrac{1}{10} }$

$\: \: \: \: \rm \: \implies \: </p><p>Frequency \: = \dfrac{1 \times 10}{ 1}$

$\: \: \: \rm \: \implies \: Frequency \: = 10 \: Hz$

So, the Frequency is 10 Hz