Question

A pendulum oscillates 100 times in 50 seconds. Find its time period and frequency.​

Answer 1

Given :-

• no. of oscillations = 100
• time taken = 50 seconds

To Find :-

• frequency and time period ?

Solution :-

• Frequency of oscillations is defined as the number of oscillations of a vibrating body per second. It is given by

$\boxed{ \bold{frequency = \frac{ no. \: of \: oscillation }{time \: taken}}}$

$\bold{: \implies f = \cancel\frac{100}{50} } \\ \\ \bold{: \implies 2 \: hz} \: \: \: \: \: \: \: \:$

• The time required to complete one oscillation is known as time period. It is given by the inverse of the frequency.

$\boxed{ \bold{time \: period = \frac{1}{frequency} }}$

$\bold{: \implies t = \cancel \frac{1}{2} } \: \: \: \\ \\ \bold{: \implies t = 0.5 }$

hence,

• Frequency = 2 heartz

• Time period = 0.5 seconds

Answer 2

❥Answer

By using formula:-

No of oscillation/time 100/50=2

Time period(T)=1/v=1/2

=0.5 sec