Question

A pendulum oscillates 270 times in 30 seconds find its frequency and time period

Answer 1

Time period= time taken/ no of oscillations

= 30/270= 1/9 =0.1 sec

Frequency= no of oscillations / sec

270/30

= 9 Oscillations

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Answer 2

The time period is $0.9 sec$  and the frequency is $\frac{10}{9} Hz.$

Step-by-step explanation:

Given,

Time = $30sec$

Number of oscillations = $270$

First we calculate the time period.

$Time period(T) = \frac{Time taken}{no of oscillations}$

                   $T = \frac{30}{270}$

                  $T= \frac{1}{9}$

                  $T =0.9sec$

Now,

               $frequency (f)= \frac{1}{T}$

               $f = \frac{1}{0.9}$

               $f = \frac{10}{9} Hz$

Therefore, the time period is $0.9 sec$  and the frequency is $\frac{10}{9} Hz.$