Question

A pendulum oscillates 40 times in 4 second. Find its time period and frequency.​

Answer 1

Answer:

time period=40/4=10s

frequency=1/time period=1/40hz

Answer 2

$\tt\huge\bold\blue{ANSWER}$

Given-

• Number of oscillations = 40 times
• Time = 4 seconds

To find the frequency(v) of pendulum-

$\tt{frequency(v) = \tt{\frac{number \: of \: oscillations}{time}}}$

$\tt{frequency(v)= \tt{\frac{40}{4} =10hz}}$

Now, to find time period(T)-

$\tt{time \: period = \tt{\frac{1}{frequency \: of \: oscillations} = \tt{\frac{1}{10} = 0.1s}}}$

So, the time period of pendulum is 0.1 seconds and frequency of pendulum is 10 Hz.

____________________________________________

$\huge\tt\bold\purple{Additional \: information} -$

• Frequency of oscillations is defined as the number of oscillations of a vibrating body per second.

• The time taken by the vibrating body for one complete vibration (oscillation) is called time period. It is given by the inverse of the frequency.

• Th SI unit of frequency is Hertz (Hz).

• A bigger unit of frequency is called kilohertz. ( 1 KHz = 1000 Hz)

_________________________________________________