Question

A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency.​

Answer 1

Answer:

Time = 4 sec.

Time Period = (Time taken) / (Number of Oscillations)

Time Period = (4/40) = 0.1 sec.

Frequency = (Number of Oscillations)/ (Time taken)

Frequency = (40/4) =10Hz.

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Answer 2

$\huge\underline{\overline{\mid{\bold{\red{ANSWER࿐}}\mid}}}$

$\bf\underline{\underline{\red{GIVEN :}}}$

• Oscillates 40 times in 4 seconds.

$\bf\underline{\underline{\red{TO FIND :}}}$

• Find its time period & frequency.

$\bf\underline{\underline{\red{SOLUTION :}}}$

Time Period,

Time period = Time/No. of oscillations in time

→ Time period = 4/40

→ Time period = 0.1 sec

Frequency,

Frequency = 1/Time period

→ Frequency = 1/0.1

→ Frequency = 10 Hz

Hence, the time period is 0.1 sec & frequency is 10 Hz.

Hope it Helps Buddy ♥️