Question

A pendulum oscillates 40 times in 4 seconds. find its time period and frequency​​

Answer 1

$\bold{Answer=>}$

The number of oscillations of a vibrating body per second is known as $\bold{frequency\: of \: oscillations}$

$frequency = \frac{no. \: of \: oscillations}{time}$

= 40 / 4 = Hz

The time required to complete one oscillation is known as $\bold{Time \: period}$.

= It is given by the inverse of the frequency.

$time \: period = \frac{1}{frequency \: of \: oscillation }$

= 1 / 10 = 0.1s

Answer 2

Explanation:

Frequency is defined as the number of oscillations per unit time. Time = 4 sec. Time Period = (4/40) = 0.1 sec. Frequency = (Number of Oscillations)/ (Time taken)Frequency = (40/4) =10Hz.

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