Question

A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency.​

Answer 1

Frequency is defined as the number of oscillations per unit time. Time = 4 sec. Time Period = (4/40) = 0.1 sec. Frequency = (Number of Oscillations)/ (Time taken)Frequency = (40/4) =10Hz.

I hope this helps.

Answer 2

$frequency= 10\;Hz$Answer:

Hence the time period of the pendulum is $0.1\; sec$ and the frequency of the pendulum is $10\;Hz$.

Explanation:

As per the data provided in the question,

The given data is as follows.

We have a pendulum that oscillates 40 times in 4 seconds.

We have to find its time period and frequency.

We will use the formula of frequency.

$Frequency =\frac{Number \;of \;oscillations}{Time\;taken}$

We will substitute the value in the above formula.

$Frequency=\frac{40}{4}$

Now, we will divide by 2.

$Frequency=\frac{20}{2}$

Again, we will divide 20 by 2 we get 10

$frequency= 10\;Hz$

Again we will use the formula of the time period.

We will substitute the value in the above formula.

$Time \;period=\frac{4}{40}$

Now, we will divide by 2

$Time \;period=\frac{2}{20}$

Again, we will divide 2 by 20, we get 0.1.

$Time \;period=0.1\;sec$

Hence the time period of the pendulum is $0.1\; sec$ and the frequency of the pendulum is $10\;Hz$.