Question

a pendulum oscillates 425 times in 40 seconds .find the time period and frequency​

Answer 1

Answer:

Frequency is defined as the number of oscillations per unit time. Time = 4 sec. Time Period = (4/40) = 0.1 sec. Frequency = (Number of Oscillations)/ (Time taken)Frequency = (40/4) =10Hz.

Answer 2

Given :-

Time taken by the pendulum = 40 sec

Number of oscillation by the pendulum = 425 times

To Find :-

Time period of the pendulum.

Frequency of the pendulum.

Analysis :-

Here we are given with the time taken and the number of oscillation of the pendulum.

Firstly, in order to find the time period substitute the given values accordingly such that time period is equal to time taken by number of oscillations.

Then find the frequency by substituting the values we got such that frequency is equal to one divided by time period.

Solution :-

We know that,

• f = Frequency
• t = Time

Using the formula,

$\underline{\boxed{\sf Time \ period=\dfrac{Time \ taken}{Number \ of \ oscillation} }}$

Given that,

Time (t) = 40 sec

No. of oscillation = 425

Substituting their values,

⇒ 40/425

⇒ 0.094

Therefore, the time period of the pendulum is 0.094.

Using the formula,

$\underline{\boxed{\sf Frequency=\dfrac{1}{Time \ period} }}$

Given that,

Time period = 0.094

Substituting their values,

⇒ 1/0.094

⇒ 10.63

Therefore, the frequency of the pendulum is 10.63.