Question

A pendulum oscillates 60 times in 4 seconds, its frequency and time period will be- *





10 Hz and 0.01 sec.

15 Hz and 0.01 sec.

15 Hz and 0.06 sec.

240 Hz and 15 sec.​

Answer 1

Answer:

It will be 15 Hz and 0.06 sec

Explanation:

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Answer 2

Given:

• Number of oscillation =60

• Time =4 seconds

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To Find :

• Frequency =?

• Time period =?

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Formula :

$\\ \red \bigstar \boxed{ \boxed{ \sf{time \: period \: = \frac{time}{number \: of \: oscillations} }}}$

$\red \bigstar \boxed{ \boxed{ \sf{frequency = \frac{1}{time \: period} }}}$

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Solution :

$\\ \implies \sf \: time \: period = \frac{time}{number \: of \: oscillation} \\ \\ \\ \implies \sf \: time \: period = \frac{4}{60} = \frac{2}{30} = \frac{1}{15} \\ \\ \\ \implies \sf \: time \: period = \frac{1}{15} \\ \\ \\ \implies \boxed{ \sf{time \: period \: =0.066 \: seconds }}$

$\implies \bf \: frequency = \frac{1}{time \: period} \\ \\ \implies \sf \: frequency = \frac{1}{0.06} \\ \\ \\ \implies \sf \: frequency = \frac{100}{6} \\ \\ \\ \implies \sf \: frequency = 16.66 \approx = 15 \: hertz \\ \\ \\ \implies \boxed{ \boxed{ \sf{ frequency = 15 \: hertz}}}$

Therefore , Time period =0.06 second and frequency =15 hertz