Question

A pendulum oscillates 80 times in second find its time period and frequency
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Answer 1

Answer:

no of oscillation in 8 secs=80

no of oscillations in one second=80/8=10

frequency is 10Hz

Time period=1/frequency = 0.1 sec

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Explanation:

Answer 2

The frequency is 80Hz and the Time period is 0.0125s.

Explanation:

• The frequency of a wave or wavering is characterized as the number of cycles or completed variations per unit time.
• f=N/t ⇒ 80/1 =80Hz
• Frequency and time period are contrarily relative.
• The sum of time it takes for something to total one swaying is called its time period.
• period = 1/Frequency ⇒ T = 1/80 =0.0125s