Question

A Pentagon has five external angles.
Angle 1 angle 90 degrees angle 40 degrees angle 90 degrees angle 60 degrees find the value of x

Answer 1

$\angle \: a_{1} = 90 \degree \\ \angle \: a_{2} = 40 \degree \\ \angle \: a_{3} = 90 \degree \\ \angle \: a_{4} = 60 \degree \\ let \: \angle \: a_{5} \: be \: x \\ sum \: of \: all \: \angle \: s \: in \: pentagon = 540 \degree \\ = > 90\degree + 40 \degree + 90 \degree + 60 \degree + x = 540 \degree \\ = > 280 \degree+ x = 540 \degree \\ = > x = 540 \degree - 280 \degree \\ = > \bold {x = 260 \degree}$

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