Question

a perametere of arectangular field is 360metere and berdth is 72 metere find the length​

Answer 1

Step-by-step explanation:

perimeter of rectangle is = 2(L+B)

360 = 2(72 + B)

360/2 = 72+B

180= 72+B

180-72= B

108= B

Answer 2

$\underline{\underline{\sf{ \color{lime}{Given \: that:-} }}} \: \bf \: Perimeter = 360 \: m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf length = 72 \: m \\ \bf \purple {Perimeter \: of \: rectangle=2 ( l+b)} \\ \bf \green{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 360 \: m = 2(72 + b)} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \red{360 \: m = 144 + 2b} \\ \: \: \: \: \: \: \: \: \: \: \: \bf \blue{ 2b = 360 - 144} \\ \: \: \: \: \: \: \: \bf \purple{2b = 216} \\ \: \: \: \: \: \:\bf \orange{ b = \cancel \frac{216}{2} = 102}$

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